Anonymous School
(Minds of Hacker)
--------------------------------
Create two classes DM and DB which store the value of distances. DM stores distances in metres and centimetres and DB in feet and inches. Write a program that can read values for the class objects and add one object of DM with another object of DB. (Use a friend function to carry out the addition operation. The object that stores the results may be a DM object or DB object, depending on the units in which the results are required.)
 |
#include<iostream>using namespace std;class DB;class DM{float meter,centi;public:void getdata(){cout<<"\nEnter the distance in(meter-centimeter):";cin>>meter>>centi;}void display(){cout<<"\nThe distance is:";cout<<meter<<" meters and "<<centi<<" centimeter";}friend void add(DM &,DB &);};class DB{float inch,feet;public:void getdata(){cout<<"\nEnter the distance in(feet-inch):";cin>>feet>>inch;}void display(){cout<<"\nThe distance is:";cout<<feet<<" feet and "<<inch<<" inch";}friend void add(DM &,DB &);};void add(DM &a,DB &b){int ch;cout<<"\nPress 1 for meter-centi:";cout<<"\nPress 2 for feet-inch:";cout<<"\nEnter your choice:";cin>>ch;if(ch==1){DM d;int c=(a.meter*100+a.centi+b.feet*30.48+b.inch*2.54);if(c>=100){d.meter=c/100;d.centi=c%100;}else{d.meter=0;d.centi=c;}d.display();}else{DB d;int i=(a.meter*39.37+a.centi*.3937008+b.feet*12+b.inch);if(i>=12){d.feet=i/12;d.inch=i%12;}else{d.feet=0;d.inch=i;}d.display();}}int main(){DM a;DB b;a.getdata();b.getdata();add(a,b);}
Output:
Enter the distance in(meter-centimeter):20 34
Enter the distance in(feet-inch):10 49
Press 1 for meter-centi:
Press 2 for feet-inch:
Enter your choice:1
The distance is:24 meters and 63 centimeter
*******************Don't Make Learning Hard*****************
Follow us on :-
1) YouTube Channel :- Click Here
2) Blog :- Click Here